Stallion,
That is a good question; generally speaking, 15 parts of air are needed for each part of fuel to attain the best fuel/air ratio for an automobile engine (that's about 9,000 Gallons of air for every gallon of fuel burned, or a more simple illustration would be 1/2 teaspoon of fuel for every cubic foot of air. :j
The weight (or mass) of the fuel has to be counterbalanced by the weight of the air, but since a cubic foot of air weighs approximately 1-1/4 onces and a cubic foot of fuel weighs approximately 775 onces, then we must compensate for the weight of fuel by multiplying the ideal rate of 15 to 1 by 620 (775 onces of fuel divided by 1-1/4 onces = 620), so by multiplying 15 times 620 we get 9,300 cubic feet of air needed to burn a cubic foot of fuel in an engine. Caloric value (the amount of heat released when burned) for the fuel also plays a role in this numer.
All things being equal, that 15 to 1 rate would change if the type of fuel was changed. If for example, a new type of fuel were to be discovered, and this new fuel would weigh less that gasoline, but it would also have a higher caloric value , then the rate would be more than 15 to 1.