I found this explanation somewhere before. Maybe it will help.
When the ignition switch is turned on, voltage is supplied through the warning light to the choke heater. Under this condition, the light is illuminated and the high resistance in this bulb provides a very low current flow to the choke heater so the choke spring is not heated if the driver leaves the ignition switch on with a cold engine. With the ignition switch on, current also flows from the ignition switch through the relay winding and the alternator field to ground. This current flow keeps the relay contacts open.
Once the engine starts, the alternator supplies approximately 14 V to the entire electrical system. Under this condition, 14 V is supplied to both ends of the relay winding, and the current flow through the winding is stopped. Since this relay is normally closed, the contacts move to the closed position and supply full voltage to the choke heater to open the choke. When the choke relay contacts are closed, equal voltage is supplied to both sides of the choke warning light, and this light remains off. If a defect occurs in the system, such as a defective relay, current flows through the warning light and the choke heater to ground. This light is illuminated to inform the driver that a defect is present in the choke heater circuit.
Enigma